Answer:
There were 10 flies originally
Step-by-step explanation:
Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;
V = I(1+r)^d
where V is the number of flies on a particular day
I is the initial number of flies
r is the constant increase in percentage
and d is the number of days.
So we have for the second day;
60 = I(1+r)^2 ••••••(i)
For the fourth day, we have;
360 = I(1+r)^4 ••••••••(ii)
divide equation ii by i; we have;
360/60 = (1+r)^4/(1+r)^2
6 = (1+r)^2
(√6)^2 = (1+r)^2
1 + r = √6
r = √6 - 1
So we can substitute the value of r in any of the equations to get I which is the initial number of flies
Let’s use equation 1
60 = I(1 + r)^2
60 = I(1 + √6 -1)^2
60 = I(√6)^2
60 = 6I
I = 60/6
I = 10 flies
Answer:
i think D or B is the answer
Step-by-step explanation:
Yes it’s 15, Thats cool man
-5x^3 + 2x^2 + 1
a coefficient is the number that is multiplied by the variable.For instance, the coefficient of 2x is 2....because 2 (the number) is multiplied by the variable x.
so in ur problem....there are 2 coefficients..-5 and 2.
** the number 1 is not a coefficient, it is a constant...a " loner " with no variables (letters) attached.
** and if u have just the letter...such as n, the coefficient to that is 1 but the one is just not written...it is actually 1n.
okay...I am gonna shut up now :)
