(5y² +4y -6)(3y

Q-The circumference of the circle is also sometimes called:

Lelu [443]

Perimeter or diameter

3 0

3 years ago

A student loan you took out is due in 3 years and requires repayment of $3,000. To pay off the loan, you set aside money in an a

damaskus [11]

Answer:

P = $2448.89

P ~= $2,449

He need to deposit $2,449

Step-by-step explanation:

Given:

Interest rate r= 7% = 0.07

Number of years n = 3 years

Future value that should be meet A = $3000

We need to calculate the initial investment (Principal P). Using the compound interest formula:

A = P(1+r)^n

P = A/(1+r)^n

Substituting the values of A, r, n, we have;

P = 3000/(1+0.07)^3

P = $2448.89

P ~= $2,449

7 0

3 years ago

The sum of 11 and the product of 2 and a number r

andrew-mc [135]

Algebraically that would be expressed as 2r + 11

The product of 2 and r is 2r.

The sum of 2r and 11 is 2r + 11

5 0

3 years ago

Read 2 more answers

Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr

mixer [17]

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

<u>Oliver's Interviewees</u>

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

$\frac{70}{100} * \frac{176}{1}$

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

$\frac{30}{100} * \frac{176}{1}$

Cross multiply

52.8 were 9th-graders interviewed by Oliver

<u>Jenny's Interviewees</u>

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

$\frac{75}{100} * \frac{140}{1}$

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

$\frac{25}{100} * \frac{140}{1}$

Cross multiply

35 students were 10th-graders interviewed by Jenney.

<u />

<u>Total calculation</u>

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

<h2>Therefore, there are 36 more 10th than 9th.</h2>

<u />

<h3><u>Extra Info:</u></h3>

<u>Oliver's Interviewees Percentage</u>

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = $\frac{30}{100}$ while, 70% = $\frac{70}{100}$

Now solve it;

$\frac{30}{100} + \frac{70}{100}$

Simplify; cancel bottom zero's;

$\frac{30}{1} + \frac{70}{1}$

Add the remaining numerators;

30 + 70 = 100

Which is 100%

<u>Jenny's Interviewees Percentage</u>

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = $\frac{25}{100}$ and, 75% = $\frac{75}{100}$