Answer:
Last one:
2 x + 4 y = 6. 3 x minus 4 y = 9.
Step-by-step explanation:
2x + 4y = 6
3x - 4y = 9
4y = 3x - 9
2x + 3x - 9 = 6
5x = 15
x = 3
4y = 3(3) - 9
4y = 0
y = 0
Only one solution, which is (3,0)
Answer:
I don't know if i'm right but I think it's b.
Step-by-step explanation:
I am so sorry if I am wrong.
3/2x-7=-11
We move all terms to the left:
3/2x-7-(-11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x+4=0
We multiply all the terms by the denominator
4*2x+3=0
Wy multiply elements
8x+3=0
We move all terms containing x to the left, all other terms to the right
8x=-3
x=-3/8
x=-3/8
Answer:
Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:
X + Y = 10
X + Z = 20
+ Y + Z = 24
----------------
2X + 2Y + 2Z = 54
Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.
Step-by-step explanation:
hopefully this helps
Answer: Um...is there supposed to be a link? I'll edit my answer if there is.