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3 years ago

Evaluate 8 + 3e when e=2

Mathematics

2 answers:

maksim [4K]3 years ago

8 0

Answer:

Step-by-step explanation:

We are given the expression:

$8+3e$

and asked to evaluate when $e=2$ . Therefore, we must substitute 2 in for $e$ and solve.

$8+3(2)$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Multiply 3 and 2.

$8+6$

Add 8 and 6.

$14$

The expression 8+3e evaluated at e=2 is equal to 14

jeka943 years ago

6 0

Answer is 14.

8+3(2)

8+6 =14

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Every Wednesday, Carla runs 2.5 miles. How many feet did she run?

Inessa05 [86]

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3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

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Please help me, I don't know how to do this...

Lunna [17]

Answer:

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x^2 +2x +1 +x^2 = 61 . . . eliminate parentheses

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x = -6 or +5

The solution is x = 5.

_____

Side lengths cannot be negative. Solution values are values of x that make the factors zero. x+6=0 when x=-6, for example.

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2 years ago