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Kamila [148]
2 years ago
7

Evaluate 8 + 3e when e=2

Mathematics
2 answers:
maksim [4K]2 years ago
8 0

Answer:

14

Step-by-step explanation:

We are given the expression:

8+3e

and asked to evaluate when e=2. Therefore, we must substitute 2 in for e and solve.

8+3(2)

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Multiply 3 and 2.

8+6

Add 8 and 6.

14

The expression 8+3e evaluated at e=2 is equal to 14

jeka942 years ago
6 0

Answer is 14.

8+3(2)

8+6 =14

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Simplify the expression: the square root of -13 times the square root of -26 calculator
Rasek [7]
Sqrt -13  = sqrt13 i
sqrt  -26  =  sqrt2 * sqrt13i 

sqrt-13 * sqrt -26  = sqrt2 * 13*  i^2  = -13 sqrt2 (because i^2 = -1)

answer is -13 sqrt2
6 0
3 years ago
0.8 &gt;0.78<br> True or false?
ElenaW [278]

Answer:

true

Step-by-step explanation:

.8 is closer to 1 than .78 is

8 0
2 years ago
-4+2(12)<br> ————<br> -3(-3)-(-1)
dsp73

Answer:

20/10 is 2

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8 0
2 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
What is the answer to 2m-6=48
Marrrta [24]
2m-6=48
      +6  +6
__________
2m= 42
÷2      ÷2
_________
m=21

m=21 is the answer 
5 0
3 years ago
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