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ad-work [718]
3 years ago
5

5. Which equation is an open sentence?

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

a

Step-by-step explanation:

there is an unknown thingy which is x

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What is the equation of the line
tiny-mole [99]
The correct answer is:  [D]:  " y = - 4x − 13 " .
______________________________________________
Explanation:
_____________________________________________________

All the answer choices given are written in "point-slope format" (also known as "slope-intercept format" — that is:  " y = mx + b" .

All of the answer choices given have a slope of "-4" ; that is:  "m = -4" .
_____________________________________________________
          The only answer choice with the equation that passes through point
"(-3, 1)" — that is,  when "x = -3, y = 1"   — is:
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                     Answer choice:  [D]:  " y = - 4x − 13 " .
___________________________________________________
In the equation:  " y = - 4x − 13 " ; when  "x = - 3, y = 1" .
____________________________________________________
Given:  " y = - 4x − 13 " ;

↔   - 4x − 13 = y  ;

Plug in "(-3)" for "x" ; and see that "y = 1" ;

         -4(-3) − 13 = y  ;

          12 − 13 = y = -1  ;
______________________________
So, when x = -3, y = 1 .
_________________________________________
The correct answer is:  [D]:  " y = - 4x − 13 " .
___________________________________________
Consider choice:  [A]:  " y = - 4x + 13 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
  -4(-3) + 13 = y ;  12 + 13 = 25 ; NOT "-3" .
______________________________________
Consider choice:  [B]:  " y = - 4x + 7 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
  -4(-3) + 7 = y ;  12 + 7 = 19 ; NOT "-3" .
______________________________________
Consider choice:  [C]:  " y = - 4x − 7 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
  -4(-3) − 7 = y ;  12 − 7 = 9 ; NOT "-3" .
___________________________________________
This leaves us with "Answer choice: [D]:  " y = - 4x − 13 " ; the only remaining answer choice; which we have already confirmed is correct; so we do not need to check.
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Hope this helps!
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4 0
3 years ago
Can anybody help me please hurry
zhuklara [117]
Yoo kid for these type of problems your better o go with an app called Photomath
8 0
3 years ago
Let g be the function given by g(x) = −3x2 − 2x + 3. Evaluate g(−2). A) g(−2) = 5 B) g(−2) = 19 C) g(−2) = −5 D) g(−2) = −19
Mars2501 [29]

Answer:   C. g(-2) = -5

<u>Step-by-step explanation:</u>

g(-2) is when you replace all of the x's in the function with -2

g(x) = -3x² - 2x + 3

g(-2) = -3(-2)² - 2(-2) + 3

       =  -3(4)   +  4     + 3

       =  - 12     + 4      + 3

       =   -12            +7

       =            -5

5 0
3 years ago
Read 2 more answers
Help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Svetllana [295]
Best guess is it’s the second one but I believe it’s between A and B sorry If I’m wrong.
4 0
3 years ago
A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r
ohaa [14]

Answer:

b=2\frac23\:\sf ft

Area of triangle = 4 ft²

Area of rectangle = 6\frac23\: \sf ft^2

Area of irregular figure = 10\frac23\: \sf ft^2

Step-by-step explanation:

\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}

\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}

\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}

\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}

5 0
2 years ago
Read 2 more answers
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