AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
Answer:
On coordinate plane, 2 lines intersect at (negative 1, 4)
Step-by-step explanation:
negative 1 = -1, 4 = 4
therefore this means that this coordinate is also (-1, 4)
Answer:
3
5
÷
j
=
3
8
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
Step-by-step explanation:Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
102 ft = 12 cm1224 in = 12 cm1 in = 0.00980 cm
Answer:
C= 2.18x + 2.39
Step-by-step explanation:
