Answer:
The answer to your question is: letter B
Explanation:
Reaction
Cr2O3(s) + 3CCl4(l) ⇒ 2CrCl3(s) + 3COCl2(g)
From the information given and the reaction, we can conclude that:
Green solid = Cr2O3 (s) "s" means solid
Colorless liquid = CCl4 (l) "l" means liquid and is the other reactant
Purple solid = CrCl3(s) CrCl3 is purple and "s" solid
Then, as a green specks remains it means that the excess reactant is Cr2O3, so, CCl4 is the limiting reactant.
1. 1 M , 2 M , 1 M
2. 10 mol , 0.1 mol , 0.5 mol
3. 0.5 L , 6.6 L , 5/21 L
M = mol/L
Explanation:
Answer: 12CO2(g) +12H2O(l)->C12H24O12(s)+12O2(g)
Once you make balancing equations don't disturb the given numbers because it is fix you need to solve by the side of the chemical name.
Answer:
2H^+ +2e -> h2(g)
Explanation:
Since hydrogen is reduced, look for a decrease in oxidation number and the gain of electrons.
