Oxidation of ethanol plssss

Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa

drek231 [11]

Answer:

1. the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c ( $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$ )

Explanation:

To find -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 117 kPa

⇒Absolute pressure ( p1 ) = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 212 kPa

⇒Absolute pressure (p2) = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. $V_{1}$ = $V_{2}$

As we know that, P ∝ M

⇒ $\frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378$ ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒ $\frac{P}{T}$ ∝ M

⇒ $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$

So, The correct relation is c option.

6 0

2 years ago

Please help me!! thank you so much!!

Elis [28]

Answer:

13.75

Explanation:

gets halved every 8 days so halved twice

4 0

3 years ago

HELP PLEASE I WILL GIVE 100 PONTS

pochemuha

Answer:

boiling point

Explanation:

5 0

3 years ago

Read 2 more answers

You have 15.42g of C2H6. How many moles of H2O can be made?

Amiraneli [1.4K]

Answer: The moles of water produced are 1.54 moles.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethane = 15.42 g

Molar mass of ethane = 30.07 g/mol

Putting values in above equation, we get:

$\text{Moles of ethane}=\frac{15.42g}{30.07g/mol}=0.513mol$

The chemical equation for the combustion of ethane follows:

$2C_2H_6+5O_2\rightarrow 4CO2+6H_2O$

By Stoichiometry of the reaction:

2 moles of ethane produces 6 moles of water

So, 0.513 moles of ethane will produce = $\frac{6}{2}\times 0.513=1.54mol$ of water

Hence, the moles of water produced are 1.54 moles.

4 0

3 years ago

Identify the type of reaction depicted below: 2SO2(g) + O2(g) --> 2SO3(g)

ioda

Answer:

Combination reaction

Explanation:

In Chemistry, elements and compounds are involved in a process called chemical reactions, which are of different types namely: combination, decomposition, double replacement, combustion etc. A combination reaction is that reaction in which two or more substances called the REACTANTS combine together to form a single new substance called the PRODUCT.

In this case, a reaction is depicted as follows:

2SO2(g) + O2(g) --> 2SO3(g)

In this reaction, compound SO2 combines chemically with element O2 to form a single new compound SO3. Hence, this is a type of COMBINATION REACTION.

4 0

2 years ago

Oxidation of ethanol plssss​

Oxidation of ethanol plssss