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2 years ago

7

Oxidation of ethanol plssss

1 answer:

faltersainse [42]2 years ago

3 0

(Na2Cr2O7) all the numbers are bellow not over

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You place a balloon in a closed chamber at STP. When the balloon doubles in size, what happens to the chamber pressure? A.) The

larisa86 [58]

If you increase the volume the pressure will decrease. so the best answer is C

4 0

3 years ago

Read 2 more answers

Volume and moles are __________ related. This relationship can be calculated by using ___________ Law.

Kryger [21]

Answer:

The correct answer is - directly; Avogadro’s.

Explanation:

At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.

Thus, the correct answer is - directly; Avogadro’s.

6 0

3 years ago

What type of rays result in shorter days? (science)

OLEGan [10]

Answer:

verical rays

Explanation:

4 0

2 years ago

Which of the following ions is formed when a base is dissolved in a solution?

Aneli [31]

Answer:

$\huge\boxed{\sf OH-}$

Explanation:

<u>According to Arrhenius concept of acid and base:</u>

"When a base in a solution, produces/yields OH- (Hydroxide) ions."

So, when a base is dissolved in a solution, it produces OH- ions.

<u>For example:</u>

NaOH ⇄ Na⁺ + OH⁻ (So, it is a base)

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

3 0

2 years ago

What amount of heat is released when the temperature of 450.0 g of a

Molodets [167]

Answer:

$\boxed {\boxed {\sf 4038.48 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

$q=mc\Delta T$

The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the change in temperature is 7.1 °C.

$m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C$

Substitute the values into the formula.

$q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)$

Multiply the first 2 values together. The grams will cancel out.

$q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)$

Multiply again. This time, the degrees Celsius cancel out.

$q= 4038.48 \ J$

<u>4038.48 Joules</u> of heat energy are released.

5 0

2 years ago