The mass of sodium hydrogen carbonate : 10.5 g
<h3>Further explanation</h3>
Given
1.5 dm' of CO₂
1 mol gas= 24 L at RTP(25 °C, 1 atm)
Required
the mass of sodium hydrogen carbonate
Solution
Decomposition reaction of Sodium hydrogen carbonate :
2 NaHCO₃ (s) ⇒ Na₂
CO₃ (s) + H₂
O(g) + CO₂ (g)
mol CO₂ :

From the equation, mol ratio of NaHCO₃ : CO₂ (g) = 2 : 1, so mol NaHCO₃ :

Mass NaHCO₃(MW=23+1+12+3.16=84 g/mol) :

Answer:
3.98 g
Explanation:
Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

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Step 2. Calculate the number of moles of magnesium:

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Step 3. Calculate the number of moles of oxygen:

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Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

Equivalent of oxygen:

Therefore, Mg is the limiting reactant.
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Step 5. According to the stoichiometry of this reaction:

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Step 6. Convert the number of moles of MgO into mass:

Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
NH3 is soluble in water because it has the same amount of intermolecular forces as water. NH3 is a polar molecule and water is a polar molecule so they dissolve each other. NCl3 does not dissolve in water because it is a nonpolar molecule which is different with water. NCl3 is nonpolar due to the difference in electronegativities between 3 atoms of Cl and 1 atom if N2.