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9966 [12]
3 years ago
11

A sample of gas has a pressure of 742 torr. What is the pressure in atmospheres?

Chemistry
1 answer:
ycow [4]3 years ago
8 0

Answer:742 torr= approximately 0.976 atm

Explanation:

Since we know that one atm= 760 torr, we can compute the following calculation:

(742 torr/1)*(1atm/760torr)=0.976316 atm

Remember sig figs (3) to round it to 0.976 atm

\frac{742 torr}{1}*\frac{1 atm}{760 torr}=0.976316=0.976 atm

(torr cancels out and we're left with atm)

Hope this helps :)

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How many kilojoules are released when 116 g of Cl2 reacts with silicon? Si(s)+2Cl2(g)→SiCl4(g)ΔH=−657kJ
alexandr402 [8]

Answer:-  537 kJ of heat is released.

Solution:- For the given equation, \Delta H is -657 kJ and the coefficient of Cl_2 in the balanced equation is 2. It means 657 kJ of heat is released when 2 moles of chlorine are used. We need to calculate the heat released when 116 g of Cl_2 are used.

Grams of chlorine are converted to moles and then multiplied by the \Delta H value and divided by the coefficient of chlorine and the set could be shown using dimensional analysis as:

116gCl_2(\frac{1mol}{70.9g})(\frac{657kJ}{2mol})

= 537.46 kJ

If we use the correct sig figs then it needs to be round off to three sig figs as the given grams of chlorine has only three sig figs. So, 537 kJ of heat is released.

6 0
3 years ago
In this lab, when the solid has been filtered and is sitting on the filter paper, you have to rinse it. what would be the worst
Lelechka [254]
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3 0
3 years ago
What is the shape of a molecule that has 4 atoms bonded to a central atom
Nataliya [291]

Answer:

C. Tetrahedral

Explanation:

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4 0
3 years ago
5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres
slega [8]

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}

T_2=\frac{1.00\times 303.65}{2.40}

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T( °C) = T(K) - 273.15

          = 126.52 - 273.15 = -146.63 °C

7 0
3 years ago
How are methane and propane alike
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Both have Colorless gas, External MSDS, Phase Behavior solid, liquid, and gas. 
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