All of my teachers have told me that everyone remembers things best in groups of seven. so I would suggest to pick a continent and start in a corner and spend a couple of days studying seven countries in that area. also quiz your self every once in a while for extra help.
I hope this helps you
Answer:
Frist goes to the 1st box second line and 4th dot.
Second dont know
Step-by-step explanation:
we know that
the equation
describe a vertical parabola with vertex at point 
if 
-------> the parabola open Up and the vertex is a minimum
if 
-------> the parabola open Down and the vertex is a maximum
in this problem we have
---> because is positive (given problem)
so
The vertex is a minimum
therefore
<u>the answer is the option C</u>
Up
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
