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Ugo [173]
3 years ago
8

If a football player hits the ball with a force of 50 N, determine the reaction force.

Physics
1 answer:
mel-nik [20]3 years ago
4 0

Answer: 60

Explanation: if u hit it it will have impact and the impact added 10n

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For the following questions consider a piece of copper wire. a. What type of bond is formed between the copper atoms? b. Describ
yarga [219]

Answer:

a. metallic bond

b. the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “cloud” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

c. due to the presence of free electrons in its outer energy levels

6 0
3 years ago
Read 2 more answers
As an object falls freely near the surface of the earth, its velocity?
Vsevolod [243]

If it were possible for an object to fall freely near the surface of the Earth,

-- The direction of its velocity would always be "down"; that is, toward the center of the Earth.

-- The size of its velocity would continually increase, at the rate of 9.8 meters per second for every second it falls.

7 0
3 years ago
The rate traveled from Amarillo to Austin by a bus averages 60 miles per hour. The bus arrived in Austin after eight hours of tr
jeyben [28]

Answer:

the car would arrive after 10 hr to Austin.

Explanation:

bus average from amarllo to austin = 60 miles per hour

time takne by bus to reach austin = 8 hr

automobile average from amarllo to austin = 60 miles per hour

from the information given in the question:

60 mph ---    8 h

48 mph ---  x h

By using The inverse variation:

60 : 48 = x : 8

60* 8 = 48* x

480 = 48*x

x = 480/48

x = 10 h

the car would arrive after 10 hr to Austin.

3 0
3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
I need help with this physics question
insens350 [35]
It's impossible to describe WHERE a place is without mentioning ANOTHER place.

... Across the street from -- the bank.
... Next door to -- my house.
... 30 miles west of -- Chicago.
... Up above -- the tree.
... Two days ride out of -- Tulsa.
... Halfway home from -- school.
... Twice as far from Earth as -- the moon is.
... The first seat in -- the second row.
... Behind -- the dog's left ear.
... At the bottom of -- the pool.
... On the tip of -- my tongue.
... In the front seat of -- the car.
... I saw you in -- my dream.
... You're always on -- my mind.

The question is trying to get you to realize that to get from a reference point to a certain position, you have to know

How far
and
In what direction.
4 0
3 years ago
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