How could a sedimentary rock provide evidence that the rock cycle exists?\?

What happens if two small positively charged particles of equal magnitude are placed close to each other? A) The particles will

serious [3.7K]

That is not correct, it is C :)

7 0

3 years ago

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Particles q1, 92, and q3 are in a straight line.

NNADVOKAT [17]

The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃

<h3 /><h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The force,by the charge q₁ on the q₃;

$\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}} = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N$

The force,by the charge q₂ on the q₃;

$\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}} = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09 \ N$

The net force is the sum of the two forces;

$\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N$

Hence, the net force on q₃ will be 17.51 N.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

8 0

2 years ago

Earth is 149.6 million meters from the Sun and takes 365 days to make one complete revolution around the Sun. Mars is 227.9 mill

luda_lava [24]

Answer:

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

Explanation:

The distance of Earth from the Sun is $149.6\times 10^{9}\,m$ and of Mars from the Sun is $227.9\times 10^{9}\,m$ . Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression:

$a_{r} = \frac{v^{2}}{R}$

Since planet has translation at constant speed, this formula is applied to compute corresponding speeds:

$v=\frac{2\pi\cdot r}{\Delta t}$

Earth:

$v_{earth} = \frac{2\pi\cdot (149.6\times 10^{9}\,m)}{(365\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{earth}=29806.079\,\frac{m}{s}$

Mars:

$v_{mars} = \frac{2\pi\cdot (227.9\times 10^{9}\,m)}{(687\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{mars}=24124.244\,\frac{m}{s}$

Now, centripetal accelarations can be found:

Earth:

$a_{r,earth} = \frac{(29806.079\,\frac{m}{s} )^{2}}{149.6\times 10^{9}\,m}$

$a_{r,earth} = 5.939\times 10^{-3}\,\frac{m}{s^{2}}$

Mars:

$a_{r,mars} = \frac{(24124.244\,\frac{m}{s} )^{2}}{227.9\times 10^{9}\,m}$

$a_{r,mars} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}$

The ratio of Earth's centripetal acceleration to Mars's centripetal acceleration is:

$\frac{a_{r,earth}}{a_{r,mars}} = \frac{5.939}{2.554}$

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

7 0

3 years ago

Atoms are split at power plant to create electricity*

Rudiy27

Answer:

B. Nuclear to Electrical

Explanation:

Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.

When atoms are split, nuclear energy is released.
Some part of the mass of the atom is converted to energy.
The nuclear energy released is expressed as heat energy.
This energy is used to heat water in boilers when produces steam that are used to drive the movement of turbines.
This in turn generates electricity.

8 0

3 years ago

HELP!! LOOK AT THE PICTURE!!

Ilya [14]

E = mgh = 70*10*10 = 7000J

3 0

3 years ago

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