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sukhopar [10]
3 years ago
13

An astronaut takes an iPod onto the space shuttle. An identical iPod remains on Earth. Which statement about the pull of Earth's

gravity on the iPods is true?
 A.Earth's gravity has a stronger pull on the iPod when it is on Earth than when it is in space. B.Earth's gravity has a weaker pull on the iPod when it is on Earth than when it is in space. C.The pull of Earth's gravity is the same on both iPods because they have the same mass. D.The pull of Earth's gravity is the same on both iPods because they are identical.
Physics
1 answer:
Sergio [31]3 years ago
4 0
Choice-A is the true statement, simply because the gravitational forces between two objects get weaker when the objects get farther apart.
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Which formations are created by wave erosion?
Leokris [45]

Answer:d) Stacks

Explanation: A stack or sea stack is a geological landform consisting of a steep and often vertical column or columns of rock in the sea near a coast, formed by wave erosion. Stacks are formed over time by wind and water, processes of coastal geomorphology.

3 0
3 years ago
A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their
Rom4ik [11]

Answer:

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

4 0
3 years ago
Read 2 more answers
The car starts from a room with a constant acceleration of 5 ms-2. What path will it pass in 6 seconds and what speed will it re
Kobotan [32]

Answer: The speed will be  30 m/s .

Explanation:

Given: Initial velocity of the car: u = 0 m/s

Constant Acceleration: a = 5 m/s²

Time: t= 6 seconds

To find: Final velocity(v)

Formula:  v = u+at

Substitute values in the formula, we get

v=  0+(5)(6) m/s

⇒ v= 30 m/s

i.e. Final velocity = 30 m/s

Hence, the speed will be 30 m/s .

4 0
3 years ago
Yosef is playing with different kinds of rubber bands. Some are very narrow, and some are quite wide. Yosef is curious about the
Cerrena [4.2K]

Answer:

Yosef hypothesis could be stretching of rubber band depends on rubber band's width. It is difficult to stretch a wider rubber band in comparison to a narrow band.  

Explanation:

Width of rubber band affect how easily it can be stretched. It is found that it is difficult to to stretch a wider rubber band in comparison to a narrow band because when rubber band is narrow less molecules will be there along its width and hence less restoring force will be there so rubber can be easily stretched. On the other hand when the rubber band is wider it means more molecules  are there along its width and hence more restoring force will be there while stretching so it will be difficult to stretch a wider rubber band.

5 0
3 years ago
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A 4.0kg bowling ball sliding to the right at 8.0 m/s has an elastic head-on collision with another 4.0 kg bowling ball initially
Kisachek [45]

a)

We use the formula :

m1v1i + m2v2i = m1v1f + m2v2f

Substituting the values in:

4.0kg*8.0m/s + 4.0kg*0m/s = 4.0kg*0m/s +4.0kg*v2f

Calculating this we get:

32.0kg*m/s + 0kg*m/s = 0kg*m/s + 4.0kg*v2f

Rearrange for v2f:

v2f = \frac{32.0kg*m/s}{4.0kg}

This gives us 8.0 m/s as the final velocity of the second ball.

b)

Since the collision is assumed to be elastic it means that the kinetic energy must be equal before and after the collision.

This means we use the formula:

Ek = \frac{1}{2} *m*v^{2}+ \frac{1}{2} *m*v^{2} = \frac{1}{2} *m*v^{2} +  \frac{1}{2}*m*v^{2}

Substituting in values:

Ek = 0.5*4.0kg*(8.0m/s)^2 + 0.5*4.0kg*(0m/s)^2 = 0.5*4.0kg*(0m/s)^2 + 0.5*4.0kg*(8.0m/s)^2

This simplifies to:

Ek= 128J + 0J = 0J + 128J

This shows us that the kinetic energy is equal on each side therefore the collision is Elastic and no energy has been lost.

6 0
3 years ago
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