Question

Explain how you would determine the amount of g in 1.7 mol of Al(OH)2 and give your answer.

Answer 1

Answer:

103.7 grams

Explanation:

$Al(OH)_{2}$

Al: 1 * 26.98 = 26.98

O: 2 * 16.00 = 32.00

H: 2 * 1.01 = 2.02

26.98 + 32.00 + 2.02 = 61.00

$\frac{1.7mol}{1}$ * $\frac{61.00g}{1mol}$ = 103.7 grams of $Al(OH)_{2}$