Answer:
The heat absorbed is hence 10.751.21 J
Explanation:
The heat absorbed when 88g of water is heated from 5.8°C to 35 °C is;
Heat = m c ΔT
m = 88.0 g
c = specific heat of water = 4.184 J/g°C
ΔT = ( change in temperature) = ( 35 - 5.8)°C = 29.2°C
Equating these values into the formula, we obtain;
Heat = 88* 4.184 * 29.2
Heat = 10 751.2064 J
Heat = 10 751.21 J (2 d.p)
The heat absorbed is hence 10.751.21 J
Answer:
![0.28 \mu g](https://tex.z-dn.net/?f=0.28%20%5Cmu%20g)
Explanation:
We can write the amount of mass of radon-222 left after a time t by using the equation:
![m(t) = m_0 (\frac{1}{2})^{t/t_{1/2}}](https://tex.z-dn.net/?f=m%28t%29%20%3D%20m_0%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bt%2Ft_%7B1%2F2%7D%7D)
where
is the initial mass
t is the time
is the half-life
Substituting t = 15.2 d in the formula, we find
![m(15.2 d) = (4.38 \mu g) (\frac{1}{2})^{15.2d/3.82 d}=0.28 \mu g](https://tex.z-dn.net/?f=m%2815.2%20d%29%20%3D%20%284.38%20%5Cmu%20g%29%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B15.2d%2F3.82%20d%7D%3D0.28%20%5Cmu%20g)
Answer:PH2=0.994atm, mass of zinc=0.606g
Explanation:
Equation for the reaction is written as;
Zn(s) + 2HCl(aq) - ZnCl2(aq) + H2(g)
V= 240ml = 0.240L
T= 30.8oC = 303.8K
Ptotal= 1.036atm
Pwater = 32mmHg at 30oC = 0.042atm
Therefore
PH2 = Ptotal - Pwater
= 1.036-0.042atm
=0.994atm
But PV= nRT
n = PV/RT
= 0.994x0.240/0.0821x303.8
= 0.24/24.94
=0.009324moles
For the grams of zinc
n=mass in grams/molar mass
Mass in grams = no of moles x molar mass
=0.009324x65 = 0.606g
OPTION D IS YOUR ANSWER.............
The awnser id be it is way more harmfull