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Inessa05 [86]
3 years ago
14

Can you please help me

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

its kinda dificult to explain (easier to show) but ill do my best

Step-by-step explanation:

so for part a you wanna start from the bottom (min) and go acros to the line above 1 then  go three lines up for cookies. you should be on 3, 1

for part b its c lin decorates 21 cookies in 7 min

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Help please ! it’s one of the multiple choices
sammy [17]

Answer:

Option C

Step-by-step explanation:

\boxed{Log \ \dfrac{a}{b}=log \ a - log \ b}\\\\\boxed{(log \ a)^b=b*log \ a}

\sf log_w \ \dfrac{(x^{2}-6)^4}{\sqrt[3]{x^2+8} }=log_w \ (x^2-6)^4 - log_w(x^2+8)^{\frac{1}{3}}

                       \sf = 4*log_w \ (x^2 -6) - \dfrac{1}{3}log_w \ (x^2 + 8)

3 0
2 years ago
Can someone help with this plz??
alex41 [277]

Answer:

90 visitors

Step-by-step explanation:

36=40% so X=100%

Ratio

36/40=x/100

40x=3600

x=90

3 0
3 years ago
What are the domain and range of the function f(x) = 2^x+1?
scoundrel [369]

Answer:

Domain: (-∞, ∞)

 Range: (0,∞)

Step-by-step explanation:

Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.

However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.

The addition to 1 on the exponent shifts the function to the left but doesn't change the range.

In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).

Domain: (-∞, ∞)

 Range: (0,∞)

5 0
3 years ago
The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g
S_A_V [24]

Answer:

Required,

L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}

W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}

Step-by-step explanation:

Given volume and depth respectively,

V(x)=x^3+13x-210 and x-3

To find length and width of the rectanglular swiming pool we know,

Volume=length\timesheight\timesdepth.

Let depth=D=x-3, length=L, width=W, then

V=DLW

x^3+13x-210= LW(x-3)

LW=\frac{x^3+13x-210}{x-3}

After divide we will get x^2-3x-22 with remainder -144.

Thus,

x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW

Now to find root of,

x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}

Thus,

L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}

W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}

5 0
3 years ago
Tickets at a carnival are 25 for $5.00 or 4 for a dollar.Which is the better deal?
Tresset [83]

Answer:

2nd one

Step-by-step explanation:

6 0
3 years ago
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