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3 years ago

What would be the area of the entire figure?

Mathematics

1 answer:

OlgaM077 [116]3 years ago

6 0

Answer: 57 ft^2

find the area of the triangle and rectangle then add them together

triangle:
area of a triangle=(1/2)bh
A=(1/2)(6)(4)
A=(3)(4)
A=12

rectangle:
area of a rectangle=lw
A=(7.5)(6)
A=45

add them:
45+12=57

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What is 24.678 rounded to two decimal places

Fed [463]

It would be 20.000 because you would round down

4 0

3 years ago

Read 2 more answers

Write an equivalent expression for: 3(x-2) + 4(2x-3) Explain the steps you follow to find the equivalent expression.

natali 33 [55]

3(x-2)+4(2x-3)
Use distributive property
3(x)-3(2)+4(2x)-4(3)
=3x-6+8x-12
Combining like term
3x+8x-6-12
=11x-18. As a result, 11x-18 is another expression that equivalent for 3(x-2)+4(2x-3). Hope it help!

3 0

3 years ago

What is the value of g?<br> -5+7g=3g+ 9

Xelga [282]

Answer:

g = 7/2

Step-by-step explanation:

-5 + 7g = 3g + 9

~Add 5 to both sides

7g = 3g + 14

~Subtract 3 to both sides

4g = 14

~Divide 4 to both sides

g = 14/4 or g = 7/2

Best of Luck!

6 0

3 years ago

A student has earned scores of 87, 81, and 88 on the first 3 of 4 tests. If the student wants an average (arithmetic mean) of ex

Juli2301 [7.4K]

To find an average you take the numbers to be averaged and add them together then You take the number and divide it by the number of numbers, in this case 4, and that gives you the average.
on this problem you want to do the opposite. you know the average she wants, an 87, so you multiply it by 4. 87*4=348. then you add the three numbers you have (88,81 and 87) and you get 256.
then you subtract 256 from 348 and you get 92. 92 is your answer to check just add 87+81+88+92=348
348/4=87
87 was the average she wanted.
Hope this helped! good luck :)

4 0

3 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago