Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Hi love...
The correct answer after solving for d is D=78. That’s a quick answer, but I can give you steps on how to solve.
1. Simplify both sides of the equation
2. Isolate the variable
3. Simplify
Then you’d have the answer!
Please let me know if you need further assistance! Have a jolly evening.
~Brooke❤️
Answer:
Mehrangarh Fort.
Amber Fort. Located on the outskirts of Jaipur, the Amber Fort (also known as the Amer Fort) is a landmark of phenomenal beauty. ...
Jaisalmer Fort.
Step-by-step explanation:
Answer:
x=4
Step-by-step explanation:
AB + BC = AC
AB= 6x, BC= x-5, AC= 23
Substituting what we know
6x + x-5 = 23
Combine like terms
7x -5 = 23
Add 5 to each side
7x-5+5 =23+5
7x = 28
Divide each side by 7
7x/7 = 28/7
x=4
Answer: 1+1=2
Step-by-step explanation: Imagine you have 1 cookie, and a friend gives you 1 more, that means your total amount of cookies is 2. So that proves that 1+1=2!
