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Murljashka [212]
3 years ago
5

If the perimeter of ABCDE is 38, find the perimeter of fghij

Mathematics
1 answer:
kramer3 years ago
3 0
You cant find the answer with only this information you need to know the sides of FGHIJ
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Which of the following is the correct classification of ∆mnp if m<m=35° and m<p=47°?​
AnnZ [28]

Answer:

D. Obtuse.

Step-by-step explanation:

We are told that in \Delta MNP m\angle M=35^o and m\angle P=47^o. We are asked to classify our given \Delta MNP.

We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.

Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.

So we can set an equation as:

m\angle M+m\angle P+m\angle N=180^o

Upon substituting our given values we will get,

35^o+47^o+m\angle N=180^o

82^o+m\angle N=180^o

82^o-82^o+m\angle N=180^o-82^o

m\angle N=98^o

As measure of angle N is 98 degrees, so angle N is an obtuse angle.

Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, \Delta MNP is an obtuse triangle and option D is the correct choice.

4 0
3 years ago
Read 2 more answers
Tom went to a shop where there was a 20% off sale taking place
-Dominant- [34]
Find 20 percent of $20 by multiplying 0.20 x20

You get $4. That’s what he saved.
7 0
3 years ago
Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.
Nata [24]

\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y

\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}

\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}

\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6

6 0
2 years ago
A group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students
ValentinkaMS [17]

Answer:

A maximum of 43 students and 11 teachers can go to the trip.

Step-by-step explanation:

Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:

4 + 1 = 5

54/5 = X

10.8 = X

10 x 4 = 40

10 x 1 = 10

4 - 1 = 3

Therefore, a maximum of 43 students and 11 teachers can go to the trip.

8 0
3 years ago
30 Points! To Who Ever Can Give Me The Answer
n200080 [17]

Answer:

im sorry, the answer to what?

5 0
3 years ago
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