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2 years ago

9

Pls help me this is 7th grade (ADVANCED)

1 answer:

kiruha [24]2 years ago

8 0

Answer:

10,24,33 could form a triangle

Step-by-step explanation:

5 + 19 is not greater than 25

6 + 12 is not greater than 19

15 + 17 is not greater than 44

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The rational number 5 3/7 is equal to <br><br><br> is equal to

Andrei [34K]

Answer:

38/7 is = to 5 3/7

Step-by-step explanation:

7 0

2 years ago

Enter the answer to the problem below, using the correct number of

Setler [38]

Answer:

<h2><em>55.112</em></h2>

Step-by-step explanation:

This is correct all you do is add them up like this:

30.27

1.9

+22.952

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55.112

7 0

2 years ago

PLEASE HELP RIGHT AWAY WILL MARK BRAINLIEST!

Blababa [14]

Answer:

<u>20/48 = 42%</u>

Step-by-step explanation:

<u>Number of beige tiles</u>

48 - 8 - 6 - 9 - 5
40 - 6 - 9 - 5
34 - 9 - 5
25 - 5
20 beige tiles

<u>Probability (Beige)</u>

No. of beige tiles / Total no. of tiles
<u>20/48 = 42%</u>

3 0

1 year ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

At the school annual walk-a-thon Jessica and Maria each committed to do more laps then last year. Jessica said she would walk th

Anna007 [38]

Maria will do more laps this year, assuming that last year they didn't do one or zero laps.

3 0

3 years ago