-3, 1, and 1 maybe? That's my guess.
Answer:
-4y -6
Step-by-step explanation:
use m a t h w a y it helps alot
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
-4, 1, 2, 3
Step-by-step explanation:
I put them from least to greatest.
Answer:
yes
Step-by-step explanation:
