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Nesterboy [21]
3 years ago
7

ABC underwent a sequence of rigid transformations to give ABC. Which transformations might have taken place ?

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Either a reflection across the origin. Or a 180° clockwise rotation.

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Please include work! :)
UNO [17]

Answer:

m = 13.

Step-by-step explanation:

Recall that adding logarithmic equations, (ex: log a + log b) is the same as log (a·b). Therefore:

log 12 + log 5 = log (4m + 8)

log (12·5) = log (4m + 8)

log (60) = log (4m + 8)  **Ignore 'Log' to solve for 'm'

60 = 4m + 8  **Subtract both sides by 8

52 = 4m  **Divide both sides by 4

m = 13.

6 0
3 years ago
The greatestcommonfactor of 8, 52
Nadusha1986 [10]
The GCF is the largest number that both will divide into. Eight is the larger of the two, but 52 is not divisible by 8. The next highest value is 4. 8÷4=2 and 52÷4=13. Therefore, the GCF is 4.
6 0
3 years ago
Andre tried to solve the equation 1/4(x+12)=2 what was his mistake?
GarryVolchara [31]

Step-by-step explanation:

1. 1/4(x + 12)=2 - first isolate X'

         - 12 -12

2. 1/4(x) = -10  - 1/4  since its a fraction, you'll have to subtract not divide

-1/4    - 1/4

3. x = -10.25

Andre did the first step correctly, but on the second step he just divided 1.4 by -10, instead of subtract 1/4 from both sides.

8 0
3 years ago
PLEASE HELP ME WITH THIS IT IS DUE RIGHT NOW
Ugo [173]

Step-by-step explanation:

1. Perimeter = 2 ( 5+4) = <u>18 cm</u>

Area = 5 × 4 = <u>20 cm^2</u>

2. Perimeter = 2 (5+5) = <u>20 cm</u>

Area = 5 × 5 = <u>25 cm^2</u>

3. Cups of seed needed per sq. meter = Area of the rectangle backyard

= 6 × 7

= <u>42 </u><u>cups</u><u> </u><u>of</u><u> </u><u>seed</u>

4. Feet of fence needed = Perimeter of the Square garden

= 2(8+8)

<u>= 32 feet</u>

5. Perimeter of rectangular quilt = 2 (4+6) feet

= <u>20 feet</u>

6. Area of the room = 9 feet × 8 feet

= <u>72 feet^2</u>

4 0
2 years ago
Need help <br> Please<br> Thank u
Volgvan

Answer:

i think its b

Step-by-step explanation:

4 0
3 years ago
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