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Kaylis [27]
3 years ago
15

Please help i can't figure this problem out

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

there is a very good pdf that could help you with your math problems.

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Can someone please give me the area to this. Yes I know a=B*H but I just need the answer to this
seraphim [82]
It is actualy A = w * l

so 

A = 264

then we minus 30 which equals both areas of the triangles combined, so the final answer is......  234
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A manufacturing manager reports to the CEO that 5% of products that come off the assembly line are defective. A study is perform
grandymaker [24]

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What is the volume of a sphere with a surface area of 64 pi cm^2?
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2 years ago
Which of the following points is farthest from the origin: (0,5, (1,2), (3,-4), (6,0) (-1,-2)?
Agata [3.3K]

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Step-by-step explanation:

5 0
3 years ago
15.
boyakko [2]

Explanation:

a)

{3 \choose 2} = \frac{3!}{2!(3-2)!} = \frac{6}{2*1} = 3

{3 \choose 1} = \frac{3!}{1!(3-1)!} = \frac{6}{1*2} = 3

b) First, we have that

{n \choose k} = \frac{n!}{k!(n-k)!}

On the other hand,

{n \choose n-k} = \frac{n!}{(n-k)!(n(n-k))!} = \frac{n!}{(n-k)!k!}

Therefore, both expressions are equal. This makes sense, because selecting k elements from a group of n is the same than specify which elements you will not select. In order to specify those elements you need to select the n-k elements that will not be selected. Hence, each time you are selecting k from n, you are also selecting n-k from n, and from that reason both combinatorial numbers are equal.

4 0
4 years ago
Read 2 more answers
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