Slope is known as rise over run. Because the line is pointing "\", it is negative.
The rise, the distance from one point to another, specifically from (0,4) to (1,1) is 3, as 4-1=3. your run is 1-0=1.
So your rise over run is -3/1 or, -3.
Your y-int is where when x=0, y=?
In this case y=4 when x=0.
Your equation is
y=-3x+4
I think x= -7 but I'm not to sure
True I believe my friend.
<span>5x^2 + 5y^2 + 10x − y = 0 it is the same of </span>
<span>x^2 + y^2 + 2x −1/5y = 0
and then </span>
(x + 1)^2 - 1+ (<span><span>y−1/10)^2 -1/100=0
</span> </span>(x + 1)^2 + (<span>y −1/10)^2 =(101/100)
the center is C(-1, 1/10), and the radius is R= sqrt(101)/10
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