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3 years ago

Find the value of x and the value of y

Mathematics

1 answer:

marshall27 [118]3 years ago

5 0

Right triangle 30 60 90
short leg = 1/2 hypo = 4√2 / 2 = 2√2
so x = 2√2

long leg = short leg times √3 = 2√2 * √3 = 2√6
so y = 2√6

answer C.
x = 2√2 ; y = 2√6

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2 years ago

Renaldo will write 3/20 as a decimal. Which of the following methods should he use?

makvit [3.9K]

ANSWER

1. Multiply the fraction by 5/5 to get a denominator of 100 and then write the numerator as hundredths using a decimal point.

EXPLANATION

Renaldo wants to write

$\frac{3}{20}$

as a decimal.

He needs a denominator of 100, so he can multiply by

$\frac{5}{5}$

to obtain:

$\frac{3}{20} = \frac{3 \times 5}{20 \times 5}$

This will be

$= \frac{15}{100}$

He can now obtain the decimal equivalent as

$= 0.15$

The correct choice is option 1.

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3 years ago

Read 2 more answers

What is 10 times as much as 55,837.9?

OverLord2011 [107]

558,739 is the correct answer.

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3 years ago

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A print shop borrows $6700 from a credit union for 338 days the credit union charges simple interest at an annual rate of 10% fo

bekas [8.4K]

Answer:

The total he would have to pay back would be $7,320.44

Step-by-step explanation:

(I'm assuming you want the total amount he needs to pay back)

6700 x 0.10 = 670 per year

670 ÷ 365 = 1.835616438356164

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620.44 + 6700 = 7,320.44

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2 years ago

In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

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Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

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3 years ago