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Dima020 [189]
2 years ago
15

I just need to find the value of b

Mathematics
1 answer:
WITCHER [35]2 years ago
8 0

Answer:

straight line add up to 180 so subtract 42 from 180 thts ur answer

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Which of these values for p and a will cause the function f(x)=Pax to be an exponential growth function
vovikov84 [41]

The option are missing in the question. The options are :

A.  P = 2, a = 1

B.  $P=\frac{1}{2} ;  a =\frac{1}{3}$

C. $P=\frac{1}{2} ;  a =1$

D. P = 2, a = 3

Solution :

The given function is $f(x)= Pa^x$

So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.

When the four option being substituted in the function, we get

A). It is a constant function since $2(1^x)=2$

B). Here, the value of a is a fraction which is less than 1, so it is a decay function. $f(x)=\frac{1}{2}\left(\frac{1}{3}\right)^x$

C). It is a constant function since the value of a is 1.

D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

  $f(x)=2(3)^x$

Therefore, option (D). represents an exponential function.

4 0
2 years ago
2 (4y + 3 + y) hellppp
Yanka [14]

Answer:

10y + 6 hope this helps :)

Step-by-step explanation:

3 0
3 years ago
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HELPPPP I MARK BRAINLIEST TO CORRECT ANSWERS
azamat

Answer:

I think B option is correct ..I m 95% sure

8 0
3 years ago
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Select all statements that are true about the linear equation.
mel-nik [20]

Answer:

T/F/T/T

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4 0
3 years ago
Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Basel
Nat2105 [25]

Answer:

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step

That is (\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4} Calvin's step is the correct step.Because this is the correct way to do simplify the rational expression. And also because Nadine made a blender mistake in her operations in step

Step-by-step explanation:

Given that Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Baseline Over r Superscript 8 Baseline s Superscript negative 2 Baseline EndFraction) Superscript negative 4

Their expression can be written as below

(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}

Nadine's first step is to simplify the expression is to raise the numerator and denominator to the power of 4 to get StartFraction r Superscript negative 20 Baseline s Superscript negative 12 Baseline Over r Superscript 32 Baseline s Superscript 8 Baseline EndFraction

That is \frac{r^{20}s^{12}}{r^{-32}s^8}

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4

That is r^{-13}s^{-1}

Now simplify the given expression to check whose step is correct:

(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}

=(r^{-5}s^{-3}r^{-8}s^{2})^{-4} ( using the property \frac{1}{a^m}=a^{-m} )

=(r^{-5-8}s^{-3+2})^{-4}

=(r^{-13}s^{-1})^{-4}

Therefore (\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}

Therefore Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step.

That is (\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4} Calvin's step is the correct step .Because this is the correct way to do simplify the rational expression.And also because Nadine made a blender mistake in her operations in step

6 0
3 years ago
Read 2 more answers
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