Answer:
x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.
Step-by-step explanation:
f(x) = −x² + 50x − 264
−x² + 50x − 264 = 0
-x² + 44x + 6x - 264 = 0
-x(x - 44) + 6(x - 44) = 0
(x - 44)(-x + 6) = 0
x = 6, 44
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
8x + By + 92 = 0
(-4; 12) ⇒ x = -4; y = 12
subtitute
8 · (-4) + 12B + 92 = 0
-32 + 12B + 92 = 0
12B + 60 = 0 |subtract 60 from both sides
12B = -60 |divide both sides by 12
B = -5
Answer:
14, 22
Step-by-step explanation:
x+y = 36
2×x - y = 6
=> x = 36 - y
=> 2×(36 - y) - y = 6
72 - 2y - y = 6
-3y = -66
3y = 66
y = 22
=> x = 36 - 22 = 14