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LiRa [457]
3 years ago
10

Someone check my answers please

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

its right

Step-by-step explanation:

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Ax-bx+y=z the formula that could be used to find x
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ax-bx+y=z the formula that could be used to find x

Answer:

<h2>x=z−y/a−b</h2>

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3 years ago
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PLS TRY TO ANSWER ASAP.
Harrizon [31]

Answer:

  • <u>0.075 m/min</u>

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

<u>1. Write the equation for the volume of the cone:</u>

      V=\dfrac{1}{3}\pi r^2h

<u />

<u>2. Find the relation between the radius and the height:</u>

  • r = diameter/2 = 5m/2 = 2.5m
  • h = 5.2m
  • h/r =5.2 / 2.5 = 2.08

<u>3. Filling the tank:</u>

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

  • x/y=r/h
  • y = x . h / r

The volume of water inside the cone is:

        V=\dfrac{1}{3}\pi x^2y

        V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3

<u>4. Find the derivative of the volume of water with respect to time:</u>

            \dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}

<u>5. Find x² when the volume of water is 8π m³:</u>

       V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\  11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062m²

<u>6. Solve for dx/dt:</u>

      1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}

      \dfrac{dx}{dt}=0.03596m/min

<u />

<u>7. Find dh/dt:</u>

From y/x = h/r = 2.08:

        y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0
3 years ago
Which of the numbers below could be terms in the sequence an = 3n + 16? Check all that apply.
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It should be A. 46 because 46-16=30 which means 3•10+16=46. So it is A
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Can't see the whole problem
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YOUR ANSWER IS A
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