Write each phrase as an algebraic expression. 16 seconds faster than Aya’s time.
1 answer:
Given:
The given phrase is 16 seconds faster than Aya’s time.
To find:
The algebraic expression for the given phrase.
Solution:
Let x be the Aya’s time.
16 seconds faster than Aya’s time. It means 16 seconds less than Aya’s time.
We know that a negative sign "-" is used for less than.
16 seconds less than Aya’s time =
16 seconds faster than Aya’s time =
Therefore, the required algebraic expression is .
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Answer:
38.71% probability it was manufactured by machine A.
29.03% probability it was manufactured by machine B.
32.26% probability it was manufactured by machine C.
Step-by-step explanation:
We have these following probabilities:
A 20% probability that the chip was fabricated by machine A.
A 30% probability that the chip was fabricated by machine B.
A 50% probability that the chip was fabricated by machine C.
A 6% probability that a chip fabricated by machine A was defective.
A 3% probability that a chip fabricated by machine B was defective.
A 2% probability that a chip fabricated by machine C was defective.
The question can be formulated as:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
What are the probabilities that it was manufactured by machines A, B, and C?
Machine A
What is the probability that the widget was manufactures by machine A, given that it is defective?
P(B) is the probability that it was manufactures by machine A. So
P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So
P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So
So
38.71% probability it was manufactured by machine A.
Machine B
What is the probability that the widget was manufactures by machine B, given that it is defective?
P(B) is the probability that it was manufactures by machine B. So
P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So
So
29.03% probability it was manufactured by machine B.
Machine C
What is the probability that the widget was manufactures by machine C, given that it is defective?
P(B) is the probability that it was manufactures by machine C. So
P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So
So
32.26% probability it was manufactured by machine C.