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Lilit [14]
3 years ago
14

Does anyone know how to do this?

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0

Answer:

Hope this helped!!!

Step-by-step explanation:

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Please solve and show steps for both 23 and 24
const2013 [10]
23. The answer is D. If you multiply 0.8 by 5 you get 4 meters which means it would take 5 minutes. Multiplying it by 5 will give you a whole number therefore easier to find on the graph.

24. The answer is G. The square root of 5 is 2.23 and the square root of 2 is 1.4
3 0
3 years ago
OKAY HELP ME!! I have my answer but I need to know if it's correct!!!
Pavlova-9 [17]

Answer:

D=8p

David (d) is equal to 8 times the number of photographs Gary (p) has.

Step-by-step explanation:

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3 years ago
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You decide that you would like to buy a new notebook computer. You currently have $50 that you earned from babysitting. You can
Paraphin [41]
Okay? Whats the point? If You're trying to find out how long it would take then you would have to make $500 so 45 more hours until you can get it.
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3 years ago
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Find the value of w.<br> 108<br> 40<br> w = [?]<br> Please help
Mademuasel [1]

Answer:

maybee if you woudl actually type the problem down instead of screenshotting it some people may actually be able to see it and actually answer the problem

Step-by-step explanation:

8 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
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