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Lilit [14]
3 years ago
14

Does anyone know how to do this?

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0

Answer:

Hope this helped!!!

Step-by-step explanation:

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Angel owns 10 more DVDs than Philip. Choose an equation
ruslelena [56]

The function of the number of DVDs Angel owns (a) will be a = p + 10

<h3>How to calculate the value?</h3>

From the information, Angel owns 10 more DVDs than Philip.

The number of DVD that Philip owns was represented asp.

Therefore, the function of the number of DVDs Angel owns (a) will be:

a = p + 10

Therefore the <u>function</u> is a = p + 10

Learn more about functions in:

brainly.com/question/25638609

#SPJ1

6 0
1 year ago
Please help! I do not know how to find the unknown variables using the Pythagorean theorem. Any help will be greatly appreciated
Aliun [14]

Answer:

pythagorean theorem=a squared + b squared =c squared

where c is the hypotenus(the longest part)

Step-by-step explanation:

16 squared = 8 squared +....

16 ×16=256=8×8=64 + y

256_64=192

sq. root of 192=13.85

y=180_90=90

90÷2=45

y=45

z=45

x=13.85cm

hope you understand

3 0
3 years ago
The beginning balance on the monthly bank statement for ians checking account was $289.37 and the ending balance was $409.28, wh
Vikki [24]
He deposited $119.91
8 0
3 years ago
Read 2 more answers
Anyone want to help me? <br> no but seriously I need to finish this right now
Leona [35]
I need help to solve this problems can somebody help me
8 0
3 years ago
A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

5 0
3 years ago
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