0.0028 - 0.004 i dont know what to do

Paha777 [63]

x is -31 because you had to add -11 and -20

6 0

2 years ago

Marco can swim at a speed of 45 m/min. define how long it will take him to swim 200 m he solve the equation 45 times to equal 20

user100 [1]

Answer:

The time taken by Macro to cover 200 m at the speed of 45 meter per minute is 4.44 minutes

Step-by-step explanation:

Given as :

The speed at which Macro swim = s = 45 meter per minute

The total distance cover by Macro = d = 200 meter

Let The time taken by Macro to cover 200 m = t minutes

<u>Now, From formula </u>

Distance = Speed × time

Or, d = s × t

Or, t = $\dfrac{d}{s}$

Or, t = $\dfrac{\textrm 200 meter}{\textrm 45 meter per min }$

Or, t = 4.44 minutes

So, The time taken by Macro to cover 200 m = t = 4.44 minutes

Hence The time taken by Macro to cover 200 m at the speed of 45 meter per minute is 4.44 minutes . Answer

8 0

3 years ago

In the figure below, m

devlian [24]

Answer:

y=24

z=100

Step-by-step explanation:

5y-40=80(vertical angles)

add 40 to each side

120-40=80

z=180-80

z=100

4 0

3 years ago

Last year there were 20 girls on the volleyball team. This year the number of girls DECREASED by 10%. How many girls are on the

kykrilka [37]

Answer:

18

Step-by-step explanation:

There are 18 girls on the team this year.

If you take 20 and divide the number by 10 you will get 2.

10%=2

If you multiply 2x10 you get 20.

20-2=18

8 0

2 years ago

A researcher wishes to see if the five ways (drinking decaffeinated beverages, taking a nap, going for a walk, eating a sugary s

e-lub [12.9K]

Answer:

$\chi^2 = \frac{(21-12)^2}{12}+\frac{(16-12)^2}{12}+\frac{(10-12)^2}{12}+\frac{(8-12)^2}{12}+\frac{(5-12)^2}{12}=13.833$

$p_v = P(\chi^2_{4} >13.833)=0.00785$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(13.833,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that the drowsiness are NOT equally distributed among office workers .

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Method Beverage Nap Walk Snack Other

Number 21 16 10 8 5

The total on this case is 60

We need to conduct a chi square test in order to check the following hypothesis:

H0: Drowsiness are equally distributed among office workers

H1: Drowsiness IS NOT equally distributed among office workers

The level of significance assumed for this case is $\alpha=0.1$

The statistic to check the hypothesis is given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total}{5}$

And the calculations are given by:

$E_{Beverage} =\frac{60}{5}=12$

$E_{Nap} =\frac{60}{5}=12$

$E_{Walk} =\frac{60}{5}=12$

$E_{Snack} =\frac{60}{5}=12$

$E_{Other} =\frac{60}{5}=12$

And the expected values are given by:

Method Beverage Nap Walk Snack Other

Number 12 12 12 12 12

And now we can calculate the statistic:

$\chi^2 = \frac{(21-12)^2}{12}+\frac{(16-12)^2}{12}+\frac{(10-12)^2}{12}+\frac{(8-12)^2}{12}+\frac{(5-12)^2}{12}=13.833$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(catgories-1)=(5-1)=4$

And we can calculate the p value given by:

$p_v = P(\chi^2_{4} >13.833)=0.00785$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(13.833,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that the drowsiness are NOT equally distributed among office workers .

7 0

3 years ago

0.0028 - 0.004 i dont know what to do​

0.0028 - 0.004 i dont know what to do