With some simple rearrangement, we can rewrite the numerator as

Then factorizing the difference of squares,
, we end up with

Answer:
2/3
Step-by-step explanation:
To add fractions add the numbers on top to each other and leave the bottom numbers alone if they are the same number.

48 girls are there. Given that there is a ratio of boys to girls of 7:8. Then divide 42 boys by 7 boys which equals 6. After, multiply 6 by 8 girls equals 48 girls.
The answer is J. 1/(x^2-x)