It would reflect over the x-axis and then reflect over the y-axis
Answer:
d = 25
Step-by-step explanation:

The value of d has to satisfy the inequality
so replace d with one of the given options

We have to simplify the fraction first

Answer:
Part a) By alternate interior angles
Part b) By vertical angles
Part c) By AAA (Angle-Angle-Angle) Similarity Theorem
Part d) Triangles ABC and CDE are similar
Part e)
or 
Step-by-step explanation:
Part a)
we know that
If AB is parallel to DE
then
m<1=m<4 ------> by alternate interior angles
Part b)
we know that
m<5=m<6 -------> by vertical angles
Part c) we know that
The two triangles are similar by AAA (Angle-Angle-Angle) Similarity Theorem ------> The three corresponding angles are equal
so
m<1=m<4
m<5=m<6
m<3=m<2
Part d) we know that
If two figures are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruent
therefore
Triangles ABC and CDE are similar
Part e) Find the length side of b
Remember that
If two figures are similar, then the ratio of its corresponding sides is equal
so

substitute the values

or

Where’s the rest of the problem
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