Question

Given that f(x) = x2 – 5x – 14 and g(x) = x – 7, find (f +g)(x) and

Answer 1

Answer:

$(f+g)(x)=x^2-4x-21$

Step-by-step explanation:

We are given:

$f(x)=x^2-5x-14\text{ and } g(x)=x-7$

And we want to find:

$(f+g)(x)$

This is equivalent to:

$=f(x)+g(x)$

Therefore, by substitution:

$=(x^2-5x-14)+(x-7)$

Rearranging gives:

$=(x^2)+(-5x+x)+(-14-7)$

Combine like terms:

$=x^2-4x-21$