Its B
-130 + 240= 110
110- 56 = 54
So.. 54 is your answer
The residual value will be equal to -1.
<h3>What is residual value?</h3>
A residual is a difference between the observed y-value of a data point and the predicted y-value on a regression line for the x-coordinate of the data point. A residual is positive when the point is above the line, negative when it is below the line, and zero when the observed y-value equals the predicted y-value.
Take, for instance, we have the following data entry:
Observed value = 69.4
Predicted value = 70.4
The residual (r) would be:
Residual value = 69.4 - 70.4 = -1
Therefore the residual value will be -1
Read more about residuals at:
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Answer:
1A: 29 units²
1B: √29 units
2, 3, 4. see below
5. between 8 and 8.5
Step-by-step explanation:
1A: Split the given square up into 4 triangles and a square in the centre. You'll get 4 triangles of sides 5 and 2, and a centre square of sides 3.
Area = 4(0.5)(5 x 2) + (3²) = 29 units²
1B: Square root your answer in 1A. √29 units
Alternatively you can use Pythagoras' theorem on one of the triangles. √(5² + 2²) = √29 units
2. The area is exactly 17 units, because the area of a square is the length of its side squared. (√17)² = 17, hence the square's area is 17 units.
3. A number that can be expressed as a fraction (includes whole numbers). E.g. 1/2, 1/7, 4
4. A number that cannot be expressed as a fraction. E.g. π, e, √3
5. Consider the closest square numbers to 70. 70 is closer to 64 than 81 (difference of 6 vs 11). Hence √70 should be closer to 8 than 9. Your answer should be between 8 and 8.5.
We need to find the two equations that represents the total amount of coins Carl has that makes $26.00 and the number of quarters and dimes.
Carl has 35 dimes and 90 quarters. The equations are
and
.
Let the number of dimes be 
Let the number of quarters be 
The total number of coins is 
So, the first equation will be

The value of the coins is $26. So,

Let us solve the equations



The number of dimes is 35 and the number of quarters is 90.
Learn more:
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I would help but I’m not good with graphs