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What is the product? (x 3)(2 x minus 1) 2 x squared minus 3 2 x squared 6 x 2 x squared 5 x minus 3 2 x squared 6 x minus 3.

prohojiy [21]

The product of the function is 2x^2+ 5x - 3

We are to find the product of the functions x + 3 and 2x -1

let f(x) = x+ 3

g(x) = 2x - 1

Taking the product:

f(x)g(x) = (x+3)(2x -1)

f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)

f(x)g(x) = 2x^2 - x + 6x - 3

f(x)g(x) = 2x^2+ 5x - 3

Hence the product of the function is 2x^2+ 5x - 3

Learn more on product of functions here: brainly.com/question/25638609

5 0

3 years ago

HELP IMA GIVE BRAINLY AND A LIKE

kirill [66]

Answer: 18 animals

Step-by-step explanation:

3 out of 20 pet owners get their pet from a breeder.

To find how many animals have been bought from a breeder, you need to find 3/20 of the 122 animals.

3/20 = 0.15

122 * 0.15 = 18.3

18.3 rounds down to 18

There are 18 animals who have been bought from a breeder.

7 0

3 years ago

Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va

Nat2105 [25]

Answer:

(a square +7a+12) ÷(a+3)

5 0

2 years ago

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

lyudmila [28]

Answer:

The solution to f(x) = s(x) is x = 2012.

Explanation:

Rewrite the table and the choices for better understanding:

Enrollment at a Technical School

Year (x) First Year f(x) Second Year s(x)

2009 785 756

2010 740 785

2011 690 710

2012 732 732

2013 781 755

Which of the following statements is true based on the data in the table?

The solution to f(x) = s(x) is x = 2012.

The solution to f(x) = s(x) is x = 732.

The solution to f(x) = s(x) is x = 2011.

The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012, x = 2012.

Thus, the correct choice is the third one:

The solution to f(x) = s(x) is x = 2012.

5 0

4 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago

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