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maxonik [38]
2 years ago
9

Plzzzzzzzzzz hellppppp​

Mathematics
1 answer:
solong [7]2 years ago
5 0

Answer:

Step-by-step explanation:

With of them?

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Help fast question 1 and 2 is it c and then b for 1 and 2 will give brainliest
myrzilka [38]
For question 1 the answer is B.

for question 2 the answer is C.
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3 years ago
I got 40% off when I purchased a set of golf balls regularly priced at $20. How<br> much did I save?
lianna [129]

Answer:

$8

Step-by-step explanation:

40% times $20 = 8

BRAINLIEST PLEASE

6 0
3 years ago
2/3 divided by 2 1/2=????<br><br><br>in simplest form <br><br><br>ASAP PLEASE
8_murik_8 [283]

Answer:4/15

Step-by-step explanation:

Change the whole number into a fraction and divide both and you get 4/15 or get photomath with math problems works perfectly

4 0
3 years ago
Four more than the product of three and a number x.
saul85 [17]

Answer:

3x +4

Step-by-step explanation:

4 more= 4+

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3 0
2 years ago
Read 2 more answers
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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