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3 years ago

3.0188 rounded to the nearest thousandths

Mathematics

1 answer:

Ne4ueva [31]3 years ago

4 0

3.0200 is 3.0188 rounded to the nearest thousandth.

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Can somebody help me with this?

Ghella [55]

Answer:

x=11

Step-by-step explanation:

Since this is a 90º angle, 46º+(4x)º has to equal 90º, and you can make and solve an equation for this:

46+4x=90

4x=44

x=11

Check:

46+4x=90

46+4(11)=90

46+44=90

90=90

6 0

3 years ago

The numbers I circled in red is the questions I have to do can somebody help meh wit dis.Pls and ty .

bija089 [108]

8. 6m + 3n
11. 8r^3 - r^2
12. 3h^2 + 8

hope this helps !

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3 years ago

Josh at has a collection of 1,200 music CDs. He considers 1/6 of his collection rock music. Of the rock music CDs 20 percent by

SpyIntel [72]

Answer:

Step-by-step explanation:

Josh has a collection of 1,200 music CDs. He considers 1/6 of his collection rock music. This means that the number of rock music CDs that he has is

1/6 × 1200 = 200

Of the rock music CDs, 20 percent are by solo artist. This means that the number of CDs by solo artist is

20/100 × 200 = 40

Of the solo artist 2/5 are by female artist. It means that the number done by female solo artists is

2/5 × 40 = 16

5 0

3 years ago

The questions below walk through the use of kNN to predict the value of Y for a new point with (X1, X2)=(4, 4). Distance is calc

Nady [450]

Answer:

The Euclidean distance between the two given points is $\sqrt{2}\text{ units}$ .

Step-by-step explanation:

K-NN is used to predict the variable y for a new point with $(X_1,X_2) = (4,4)$

Distance is calculated in the Euclidean sense.

The Euclidean distance between two points is given by the formula:

$\text{Points: }(X_1, X_2), (x_1,x_2)\\\\D = \sqrt{{(x_2-X_2)}^2 + (x_1-X_1)^2}$

The point is $(x_1,x_2) = (3,5)$

The Euclidean distance between the two points is given by:

$D = \sqrt{(5-4)^2 + (3-4)^2} = \sqrt{2}\text{ units}$

Thus, the Euclidean distance between the two given points is $\sqrt{2}\text{ units}$ .

5 0

3 years ago

Which describes the cross section of a square prism that passes through vertices A, B, and C?

expeople1 [14]

Answer:

In triangle ABC one side equal $8\sqrt{2}$ and two sides equal $4\sqrt{13}$

Step-by-step explanation:

We are given a prism whose base is square with sides 8 in and height 12 in.

If we take cross section through vertices A, B and C

We will get a cross section as triangle.

In triangle ABC, sides are AB, BC and AC

AB is diagonal of top square whose side 8 in.

$AB=\sqrt{8^2+8^2}=8\sqrt{2}$

AC is face diagonal of front face.

$AC=\sqrt{8^2+12^2}=4\sqrt{13}$

BC is face diagonal of right face.

$BC=\sqrt{8^2+12^2}=4\sqrt{13}$

AC=BC≠AB

Hence, In triangle ABC one side equal $8\sqrt{2}$ and two side equal $4\sqrt{13}$

6 0

3 years ago

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