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Pie
3 years ago
14

there are 8 people fishing at lake connor: 5 have fishing licenses, and 3 do not. an inspector chooses two of the people at rand

on. what is the probability that the first person chosen does noy have a license and the second one does?​
Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

3 have a license, 5 do not have a license

the first choice is 5 out of 8, or 5/8

the second choice is 4 out of 7, or 4/7

(5/8)*(4/7)=20/56=10/28=5/14

another way to look at it is...

how many ways can you choose 2 people out of 8 people ?

8!/2!(8-2)!=8!/2!*6!=8*7/2=56/2=28 ways

how many ways can you choose 2 people out of 5 people ?

5!/2!(5-2)!=5!/2!*3!=5*4/2=20/2=10

10/28=5/14 again

call the 5 people who don't have a license A,B,C,D, and E

how can they be paired together ?

AB,AC,AD,AE,BC,BD,BE,CD,CE, and DE for a total of 10

again 10/28=5/14

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Rewrite the following integral in spherical coordinates.​
lora16 [44]

In cylindrical coordinates, we have r^2=x^2+y^2, so that

z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}

correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)

which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

4 0
2 years ago
It takes 5 builders, 18 hours to build a wall.<br>How many minutes would it take 8 builders?​
mr Goodwill [35]
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7 0
3 years ago
Where is the hundred thousand place
ozzi
The 6th to the left

4 0
3 years ago
In a candy mix there are 4 green bars for every 3 red bars. How many red bars are there if there are 200 green bars
erastovalidia [21]

Answer:

Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:

4 x : 3 y

Where  x  is equal to the number of green bars and  y is the number of red bars.

We know the number of green bars is equal to 200, so we can divide it by 4, giving us:

200 /4=50

Then we can solve for  y , the number of red bars.

// Multiple y  by 50

3 ⋅ 50 = 150

So for every 4 green bars, there are 3 red bars.

For every 200 green bars, there are 150 red bars

Step-by-step explanation:

3 0
3 years ago
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DaniilM [7]
Switch the x for -3, 2, 0, and 5 so the answer will be B
6 0
3 years ago
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