It is 9. You have to add 33y, then divide by 11 and you get x = 3y + 9
The solution to the answer is as follows:
<span>0votes</span><span>answered <span>Aug 8, 2015 </span><span><span>by </span>Shashi Kumar Evangelist <span>(3,082<span> points)</span></span></span></span><span>total coins 30
1 rupee coins 20
50 paise coins 10
1 rupee coin probability 20C11
11 coin are picked 30C11
<span>ans should be = 20C11/30C11 = 2/3</span></span>
I hope my answer has come to your help. God bless and have a nice day ahead!
m∠PQR = m∠BQR + m∠PQB
We have m∠PQR = 116° and m∠BQR = 75°. Substitute:
116° = 75° + m∠PQB <em>subtract 75° from both sides</em>
41° = m∠PQB
<h3>Answer: m∠PQB = 41°</h3>
If you would like to solve the equation 8 * g - 14 * g + 22 = 37 for g, you can calculate this using the following steps:
8 * g - 14 * g + 22 = 37
- 6 * g = 37 - 22
- 6 * g = 15 /(-6)
g = 15 / (-6)
g = - 15 / 6
g = - 5 / 2 = - 2.5
Result: g equals to - 5/2.
207 cups are in the package
(690 x 0.3) = 207
0.3=30%
