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3 years ago

HELP HELP HELP, IS IT CORRECT, ILL MARK YOU BRAINIEST - THANKYOU

Mathematics

1 answer:

Alla [95]3 years ago

7 0

Answer:

$48\pi$

Step-by-step explanation:

Volume =

$r ^{2} \times \pi \times h = 4 ^{2} \times \pi \times 3 = 48\pi$

r=4

h=3

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$13.80

Step-by-step explanation:

23% of 60 = .23 x 60

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2 years ago

Eventhough i solved it i don't understand how to fill the colors

Lisa [10]

"color the piece according to your color chart." Do you have that? If you don't, I wouldn't worry, you still did all the work and got all the answers, so your teacher should be fine with it.

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2 years ago

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Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5

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3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

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3 years ago

Find the value of the expression 6x + 3xy, when x = 2 and y = 4.

damaskus [11]

<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Substitute in the values:

6(2) + 3(2)(4)

Now just solve:

12 + 24 = 36

The answer is 36

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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3 years ago

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