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Natali5045456 [20]
3 years ago
11

Please solve all 3 I need this quick

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer: i have absolutely no idea

Step-by-step explanation:

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PLEASE HELP, URGENT
yaroslaw [1]
<span>16 / 4^3 = 4^n
4^2 / 4^3  = </span>4^n<span>
4^-1 = 4^n
-1 = n or n = -1

answer
n = -1</span>
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B

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\bf \begin{array}{ccll}&#10;\stackrel{t}{months}&\stackrel{A}{books}\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;0&80\\&#10;1&100\\&#10;2&125&#10;\end{array},    we know that on Month 0, the Books were 80

\bf \qquad \textit{Amount for Exponential Growth}\\\\&#10;A=I(1 + r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &80\\&#10;I=\textit{initial amount}\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;t=\textit{elapsed time}\to &0\\&#10;\end{cases}&#10;\\\\\\&#10;80=I(1+r)^0\implies 80=I\qquad therefore\qquad \boxed{A=80(1+r)^t}

we also know that on the first month there were 100 books,

\bf \qquad \textit{Amount for Exponential Growth}\\\\&#10;A=I(1 + r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &100\\&#10;I=\textit{initial amount}\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;t=\textit{elapsed time}\to &1\\&#10;\end{cases}&#10;\\\\\\&#10;100=80(1+r)^1\implies \cfrac{100}{80}=1+r\implies \cfrac{5}{4}=1+r&#10;\implies &#10;\cfrac{5}{4}-1=r&#10;\\\\\\&#10; \cfrac{1}{4}=r\implies 0.25=r\qquad therefore\qquad \boxed{A=80(1+0.25)^t}

now, how many books when t = 8?   A=80(1+0.25)⁸, or A=80(1.25)⁸.
7 0
3 years ago
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Step-by-step explanation:

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