19.(3/4)/(1/32)=24
20.(3/4)/(1/14)=21/2
21.(1/2)/(1/72)=36
Since line t is a transversal line all angle which are perpendicular with 63 will equal to the same value (63) and also line m is a straight line where it’s total will be 180
So,
3x + 2x + 63 = 180
5x + 63 = 180
5x = 180 - 63
5x = 117
Divide by 5 throughout
X = 23.4degrees
Answer:
Nifal received $ 4 for washing the first car.
Nifal received $ 5 for washing the second car.
4 and 5 have a sum of 9.
Step-by-step explanation:
The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:


Then, by eliminating y:

Now, let is clear
:


Nifal received $ 4 for washing the first car.
The earning for the second car is: (
)



Nifal received $ 5 for washing the second car.
4 and 5 have a sum of 9.
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.