Answer:
6√2
Step-by-step explanation:
√32+√18-1√4
√16×2+√9×2-1√2
4√2+3√2-1√2
6√2
Answer:
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
2/4 =1/2 or 50%.
A(R+T)=W
(A×R)+(A×T)=W
AR+AT=W
-AR from both sides
AT=W-AR
divide both sides by A
T=(W-AR)/A
Answer:
x=-4 x=-2
Step-by-step explanation:
x² + 6x + 8 = 0
x² +2x+4x + 8 = 0
x(x+2)+4(x+2)=0
(x+4)(x+2)
x=-4 x=-2
