To calculate the threshold frequency of the metal we use the formula,
Also,
Here, E is the energy of electron per atom, h is plank constant.
Given, binding energy of electron or for one electron,, here N is the Avogadro constant and its value is , so and plank constant,
Substituting these values in above relation we get,
.
Thus, the threshold frequency of the metal is .
The spring constant of the spring is 240.05 N/m according to the information on the question above. This problem can be solved using the spring potential energy formula which stated as PE = 1/2 * k * x^2 where PE is the spring's potential energy, k is the constant of the spring, and x is the stretched displacement<span>. (Calculation: 240.05=35*2/(0.54^2) </span>
Answer:
a).
b).rpm
c).v=0.5865 m/sec.
Explanation:
Given:
a).
The angular speed in radians per seconds is
b).
rpm
c)
Child's distance per revolution
(pi*2r) = 43.988 metres.
v=(43.988 x 0.0133333) = 0.5865 m/sec.
Answer:
The force is
Explanation:
Given that,
Diameter = 7.55 mm
Intensity of light = 3.87 kW/m²
Angle = 19.9°
Intensity of absorbed light
Intensity of incoming light
Ratio of intensities
Relation between intensity and power
...(I)
The power is
....(II)
From equation (I) and (II)
Put the value into the formula
Hence, The force is
Answer:
heeyya it is the second paragraph