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3 years ago

Energy is the ability to

Physics

2 answers:

bekas [8.4K]3 years ago

8 0

A.... As energy is the ability to do work... And exerting force and transfering heat falls under work

inessss [21]3 years ago

6 0

Energy is the ability to do work.

Answer: <span>A. do work.</span>

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A solid uniformly charged insulating sphere has uniform volume charge density p and radius R. Apply Gauss's law to determine an

RUDIKE [14]

Answer:

electric field E = (1 /3 e₀) ρ r

Explanation:

For the application of the law of Gauss we must build a surface with a simple symmetry, in this case we build a spherical surface within the charged sphere and analyze the amount of charge by this surface.

The charge within our surface is

ρ = Q / V

Q ’= ρ V '

The volume of the sphere is V = 4/3 π r³

Q ’= ρ 4/3 π r³

The symmetry of the sphere gives us which field is perpendicular to the surface, so the integral is reduced to the value of the electric field by the area

I E da = Q ’/ ε₀

E A = E 4 πi r² = Q ’/ ε₀

E = (1/4 π ε₀) Q ’/ r²

Now you relate the fraction of load Q ’with the total load, for this we use that the density is constant

R = Q ’/ V’ = Q / V

How you want the solution depending on the density (ρ) and the inner radius (r)

Q ’= R V’

Q ’= ρ 4/3 π r³

E = (1 /4π ε₀) (1 /r²) ρ 4/3 π r³

E = (1 /3 e₀) ρ r

4 0

3 years ago

2. What is the feather's initial velocity (before it is dropped) in m/s?

Dmitrij [34]

Answer: 0

Explanation: Initial velocity is 0.

7 0

3 years ago

A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the

Maurinko [17]

Answer:

(a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity $R_{0}=10\ mCi$

Time $t_{1}=4\ hours$

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

$R=R_{0}e^{-\lambda t}$

$\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})$

Put the value into the formula

$\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})$

$\lambda=0.0000154\ s^{-1}$

$\lambda=1.55\times10^{-5}\ s^{-1}$

We need to calculate the half life

Using formula of half life

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}$

Put the value into the formula

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}$

$T_{\dfrac{1}{2}}=44.719\times10^{3}\ s$

$T_{\dfrac{1}{2}}=11.3\ hr$

(b). We need to calculate the value of N₀

Using formula of $N_{0}$

$N_{0}=\dfrac{3.70\times10^{6}}{\lambda}$

Put the value into the formula

$N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}$

$N_{0}=2.38\times10^{11}\ nuclei$

(c). We need to calculate the sample's activity

Using formula of activity

$R=R_{0}e^{-\lambda\times t}$

Put the value intyo the formula

$R=10e^{-(1.55\times10^{-5}\times30\times3600)}$

$R=1.87\ mCi$

Hence, (a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

4 0

3 years ago

A Boy can raise a load of 200N up to a<br>height of 2.5m in 15 seconds. calculate his<br>power

shtirl [24]

Explanation:

f=mg

=200×10

=200N

Now,

work done=df

25×200

=500J

7 0

3 years ago

Which statements best describe the work of Marie and Pierre Curie? Check all that apply.

AleksAgata [21]

B. They came up with the term “radioactivity.”

C. They conducted experiments with uranium-containing minerals and pure uranium.

E. They discovered two new radioactive elements

4 0

3 years ago

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