Hi there!
We can begin by solving for the time it takes the projectile to reach the ground.
Use the equation:
Plug in the given height:
Use the equation:
d = vt, to solve for the horizontal distance:
d = (54)(8.536) = 460.944 m
Answer:
Electric Field at a distance d from one end of the wire is
Electric Field when d is much grater than length of the wire =
Explanation:
Given:
- Total charge over the length of the wire = Q
- Length of the wire = L
- Distance from one end of wire at which electric field is needed to find=d
Let dE be the Electric Field due to the small elemental charge on the wire at a distance x from the one end of the wire and let be the charge density of the wire
Now integrating it over the entire length varying x from x=d to x=d+L we have and replacing we have
When d is much greater than the length of the wire then we have
1+\dfrac{L]{d}≈1
So the Magnitude of the Electric Field at point P =
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