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Effectus [21]
3 years ago
12

Tell me that all answers plz

Physics
2 answers:
ki77a [65]3 years ago
8 0

Answer:

a. Value of MA is always lesser than VR because mechanical advantage decreases due to the friction and weight of moving parts of the machine.

b.Efficiency of lever is never 100 or more because it will always lose some tiny (sometimes immeasurable) percentage of power due to the lever bending. 

c.Because it helps to apply more torque.

d.Because the upright snip has the blades rotated 90° from the handles. 

e.because some of the input work is used to overcome friction.

f.because the load arm is always longer than effort arm. 

g.because the effort arm is always longer than load arm of these Lever.

h. because if the effort distance is greater than load distance there will be magnification of force and the metals could easily cut.

i. because the wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull.

maksim [4K]3 years ago
3 0

Answer:

Tell me that all answers plz

No spammers

Lesson: simple machine

Great answer will be brainliest answer

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What is the difference between condensation and conduction
aniked [119]

Answer:

Convection is the heat transfer due to the bulk movement of molecules within fluids such as gases and liquids, including molten rock. Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds. These clouds may produce precipitation, which is the primary route for water to return to the Earth's surface within the water cycle.

Explanation:

Their a difference....... A huge One

8 0
4 years ago
"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th
Semenov [28]

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

7 0
3 years ago
A 2.1 cm length of tungsten filament in a small lightbulb has a resistance of 0.067 ω. find its diameter. the resistivity of the
kkurt [141]
The resistance of an ohmic material is given by 
R= \frac{ \rho l}{a}
where l is the length and a is the cross sectional area.  For a circular wire, this area is that of a circle:
R=  \frac{\rho l}{ {d^2} } \frac{4}{\pi}=\frac{5.6\times10^-8 \times0.021m\times4}{\pi d^2}   = \frac{1.497\times 10^-9}{d^2}
Then solving for diameter, d:
d^2=\frac{1.497\times 10^-9}{0.067}=2.235\times10^-8
d=0.1495mm
3 0
4 years ago
Cual es la fuerza electrica sobre el electrón (-1.6 x 10¹⁹c) de un atomo de hidrógeno ejercida por el protón (1.6 x 10¹⁹c)? Supó
kkurt [141]

Answer:

La  fuerza eléctrica es -8.2*10⁻⁸ N

Explanation:

El enunciado correcto es: <em>¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m</em>

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.

La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

F=K*\frac{q1*q2}{d^{2} }

donde:

  • F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
  • q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
  • d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
  • K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹ \frac{N*m^{2} }{C^{2} }.

En este caso:

  • F=?
  • K= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= -1.6*10⁻¹⁹ C
  • q2= 1.6*10⁻¹⁹ C
  • d= 5.3*10⁻¹¹ m

Reemplazando:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{(-1.6*10^{19} C)*(1.6*10^{19} C)}{(5.3*10^{-11} )^{2} }

Resolviendo:

F= -8.2*10⁻⁸ N

<u><em>La  fuerza eléctrica es -8.2*10⁻⁸ N</em></u>

6 0
3 years ago
Drag the tiles to the boxes to form correct pairs. Match each hypothesis for how the Moon formed with the statement that best de
Roman55 [17]

Answer:

giant impact theory

Explanation:

i don't know  im just guessing

3 0
3 years ago
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