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chubhunter [2.5K]
4 years ago
10

Ava and her little sister, April, both have the same birthdays on the same day. Ava is 12 years old, April is nine years old. Di

d you know that Ava was once double the age of April?How many years ago was that? WORTH 50 PTS PLZ ANSWER
Mathematics
2 answers:
Pavlova-9 [17]4 years ago
7 0

Answer:

6 Years ago

Step-by-step explanation:

6 years ago, Ava was 6 and April was 3, making Ava double her age.

const2013 [10]4 years ago
4 0

Answer:

6 years ago

Step-by-step explanation:

12 - 6 = 6

9 - 6 = 3

3 * 2 = 6

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Answer:

There are now 6.5 ounces in the new bag.

Step-by-step explanation:

To solve this question, take 30% of 5 and add it to the original amount of 5

30% = 0.30

5 * 0.30 = 1.5

5 + 1.5 = 6.5 ounces of candy.

Hope this helps!

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2 years ago
Please help this is due tomorrow ​
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Answer:

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3 years ago
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3 years ago
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The triangle below is equilateral. Find the length of side x to the nearest tenth.
Gemiola [76]

Answer:

\sqrt{\frac{15}{2} } or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}

x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

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x^{2} =\frac{15}{2}

x=\sqrt{\frac{15}{2} }

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2 years ago
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