Question

At which value(s) of x does the graph of the function F(x) have a vertical asymptote? Check all that apply.

Answer 1

Answer:

x = - 2, x = 1

Step-by-step explanation:

Given

f(x) = $\frac{x}{(x+2)(x-1)}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving for x gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

(x + 2)(x - 1) = 0

x + 2 = 0 ⇒ x = - 2

x - 1 = 0 ⇒ x = 1

Vertical asymptotes occur at x = - 2 and x = 1

Answer 2

Answer:

-2 is the only correct answer