At which value(s) of x does the graph of the function F(x) have a vertical asymptote? Check all that apply.
2 answers:
Answer:
x = - 2, x = 1
Step-by-step explanation:
Given
f(x) =
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving for x gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
(x + 2)(x - 1) = 0
x + 2 = 0 ⇒ x = - 2
x - 1 = 0 ⇒ x = 1
Vertical asymptotes occur at x = - 2 and x = 1
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Answer:
The answer is
<h2>Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation we must first find the slope of the line.
So the slope of the line using points (-3, 7) and (9,-1) is
<h3>Now we use the formula
<h3>y - y1 = m(x - x1)</h3>where
m is the slope
( x1 , y1) is any of the points given
So the equation of the line using point
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<h3>We have the final answer as
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Answer:
x = 40°
Step-by-step explanation:
Given that ∠SRT ≅ ∠STR
Then ∠STR = 20
∠STR and ∠STU are what you call supplementary angles. This means that the sum of their measurements is equal to 180° because they form a straight line.
So if:
∠STR + ∠STU = 180°
m∠STU = 4x
m∠STR = 20
Then:
4x + 20° = 180°
Now we solve for x:
x = 40°