Question

What’s the answer to this question if your right I’ll keep giving you points

Answer 1

$\huge\text{ m\angle O=\boxed{11^{\circ}} }$

Since we know that all angles in a triangle add up to $180^{\circ}$, we can solve for $x$ and substitute it back into $(x-5)^{\circ}$ to find $m\angle O$.

$\begin{aligned}m\angle N+m\angle O+m\angle P&=180\\(5x-8)+(x-5)+(6x+1)&=180\end{aligned}$

Remove the parentheses and combine like terms.

$\begin{aligned}5x-8+x-5+6x+1&=180\\(5x+x+6x)+(-8-5+1)&=180\\12x-12&=180\end{aligned}$

Add $12$ to both sides of the equation.

$\begin{aligned}12x-12&=180\\12x&=192\end{aligned}$

Divide both sides of the equation by $12$.

$\begin{aligned}x=16\end{aligned}$

Now that we have the value of $x$, we can substitute it back into $(x-5)^{\circ}$ to find $m\angle O$.

$\begin{aligned}m\angle O&=(x-5)\\&=16-5\\&=\boxed{11}\end{aligned}$