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Rudik [331]
3 years ago
7

-3(2x - 4) distributive property

Mathematics
1 answer:
inna [77]3 years ago
6 0

Answer:

-6x + 12

Step-by-step explanation:

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4 bells toll together at 9 am. They toll after 7, 8. 11 and 12 seconds respectively. How many times will they toll together agai
Svetach [21]

Answer:

5 times

Step-by-step explanation:

What we need to do here is to find the lowest common multiple of 7,8,11 and 12

This is;

1848

Now, let’s calculate the number of seconds in 3 hours

In 1 hour, we have 3600 seconds

In 3 hours, this will be;

3600 * 3 = 10,800 seconds

So, to find the number of times in which all 4 will toll together, we need to know the number of 1848 seconds in 10,800 seconds

Mathematically, that will be;

10,800/1848 = 5.844

Our answer will be 5 times however

This is because the sixth time they would have sounded together would be more than the 3 hours time frame

8 0
3 years ago
if one face of a cube has an area of 6.75 square inches , what is the surface area of the entire cube ?​
Travka [436]

Answer:

40.5

Step-by-step explanation:

a cube has 6 faces so 6.75 x 6 = 40.5

3 0
3 years ago
Consider the function y = cos (x + pi/6). Which of the following is true?
max2010maxim [7]
The answer would be A. There is a phase shift to the left. Because you are adding pi/6.
7 0
3 years ago
Read 2 more answers
Evaluate the expression for X=6 y= -1 4x + 5y
rodikova [14]
<h2>Answer:</h2>
  • 19 ans.
<h2>Step-by-step explanation:</h2><h3>Given:</h3>
  • x = 6
  • y = -1
<h3>To Find:</h3>
  • Evaluate 4x + 5y
<h3>Solution:</h3>

We know the value of x and y,

x = 6 and y = -1 [Given]

<u>Substitute the </u><u>value,</u>

  • 4x + 5y
  • 4(6) + 5(-1)
  • 24 + (-5)
  • 24 - 5
  • 19 Ans.
8 0
2 years ago
Please help it’s urgent
katrin2010 [14]

\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

5 0
4 years ago
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